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    • #13316
      pmngrad
      Participant

      Quick question of clarification,

      If a particular receptor has a dissociation constant (Kd) of 50nM for instance. That means that the receptor is half bound by ligand when the concentration of the ligand is 50nM.

      To fully saturate a receptor, would one use twice as much ligand? 100nM in this case?

      Thanks for your help with this….

      All the best 🙂

    • #99754
      JackBean
      Participant

      not really, it’s similar as Michaelis with enzymes, so you won’t get twice so much bound ligands 😉

      Usually, 10× more is taken to fully saturate 😉

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