Biology Forum › Cell Biology › Equilibrium
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January 16, 2011 at 3:44 pm #14383
hannahzarzar
ParticipantIn a series of reactions, A → B → C → D, it was determined that the equilibrium constant for the second reaction (B → C) is 0.1. You would expect the concentration of C in a living cell to be: (1) equal to B; (2) one tenth of B; (3) less than one tenth; (4)ten times that of B; (5) more than ten times of B. (Circle any correct answer).
In my opinion, the answer would be 3 because there are still more stages that need to bring the reaction to equilibrium. Is that right???
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January 16, 2011 at 6:03 pm #103177
JackBean
Participantif is there equilibrium and no other reactions, it should be 2
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January 17, 2011 at 5:11 pm #103190
jonmoulton
ParticipantBut this is a living cell, and so it is not at equilibrium [ Jack, you tricky guy — making a student THINK 😉 ]
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January 17, 2011 at 10:06 pm #103195
JackBean
Participantwell, even in the tube the equilibrium doesn’t mean there’s no reaction
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January 17, 2011 at 11:41 pm #103199
hannahzarzar
ParticipantThe question mentions that there are a series of reactions – A thru D. It mentions that B is 0.1. Doesn’t the equation have to total 1 in order to have equilibrium?
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January 18, 2011 at 6:35 am #103208
JackBean
Participantno, only for the particular reactions
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January 20, 2011 at 4:00 pm #103263
hannahzarzar
ParticipantSo, how am I to know how to calculate the answer? I’m totally lost on this question.
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November 25, 2011 at 2:12 pm #108412
JackBean
Participantthe equilibrium constant is calculated as follows: K = [product]/[substrate], thus, if K = 0.1 = [product]/[substrate] -> [substrate] = 10[product]
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