Equilibrium

last updated by

JackBean 13 years, 1 month ago

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- January 16, 2011 at 3:44 pm #14383
  hannahzarzar
  Participant
  In a series of reactions, A → B → C → D, it was determined that the equilibrium constant for the second reaction (B → C) is 0.1. You would expect the concentration of C in a living cell to be: (1) equal to B; (2) one tenth of B; (3) less than one tenth; (4)ten times that of B; (5) more than ten times of B. (Circle any correct answer).
  In my opinion, the answer would be 3 because there are still more stages that need to bring the reaction to equilibrium. Is that right???
- January 16, 2011 at 6:03 pm #103177
  JackBean
  Participant
  if is there equilibrium and no other reactions, it should be 2
- January 17, 2011 at 5:11 pm #103190
  jonmoulton
  Participant
  But this is a living cell, and so it is not at equilibrium [ Jack, you tricky guy — making a student THINK 😉 ]
- January 17, 2011 at 10:06 pm #103195
  JackBean
  Participant
  well, even in the tube the equilibrium doesn’t mean there’s no reaction
- January 17, 2011 at 11:41 pm #103199
  hannahzarzar
  Participant
  The question mentions that there are a series of reactions – A thru D. It mentions that B is 0.1. Doesn’t the equation have to total 1 in order to have equilibrium?
- January 18, 2011 at 6:35 am #103208
  JackBean
  Participant
  no, only for the particular reactions
- January 20, 2011 at 4:00 pm #103263
  hannahzarzar
  Participant
  So, how am I to know how to calculate the answer? I’m totally lost on this question.
- November 25, 2011 at 2:12 pm #108412
  JackBean
  Participant
  the equilibrium constant is calculated as follows: K = [product]/[substrate], thus, if K = 0.1 = [product]/[substrate] -> [substrate] = 10[product]
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