I am having trouble understanding how to figure out the ratio of genotypes and phenotypes.
The question says: There is an allele E which codes for unattached earlobes in humans. The allele e codes for the attached earlobes which do not hang free. If a ee male marries a Ee female what gametes could each parent produce? Father: Mother:
Second part of the question is: what possible genotypes could their children have? What possible Phenotypes?
I did a punnet square with Ee and ee to find the gamestes but I got the same answer for the second part of the question. Help me please im so confuse.
The first question isn’t about offspring, it’s just about gametes. You don’t need to draw a punnett square until the second question. You’re doing more work than it is asking you to do.
lowercase i is recessive and uppercase I is dominant, but there are actually two codominant alleles. I^A is dominant allele for type A, and I^B is dominant allele for type B.
There is only an exception if the have the Bombay phenotype, which involves alleles (denoted h & H) in another part of the genome.
Individuals with the rare Bombay phenotype (hh) do not express H antigen (also called substance H), the antigen which is present in blood group O. As a result, they cannot make A antigen (also called substance A) or B antigen (substance B) on their red blood cells, whatever alleles they may have of the A and B blood-group genes, because A antigen and B antigen are made from H antigen.