Is this right - Biology Forum

last updated by

mith 17 years ago

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- November 6, 2007 at 4:35 am #8519
  jjfptl
  Participant
  Hi,
  I have a problem in genetics and I was wondering if it is correct, I am pretty sure this is right, just want to make sure:
  Mutants 1, 2, 3, and 4 were analyzed and each was found to accumulate one compound (A – D), as indicated in the following table.
  Mutant Accumulation
  1 A
  2 B
  3 D
  4 D
  The pathway for phenylalanine biosynthesis is given below. Place mutants 1,2,3 and 4 in the pathway to show the reaction each gene catalyzes.
  X -> R -> B -> A -> D -> phenylalanine
  ANSWER : X -> R (2) -> B (1) -> A (3,4)-> D -> phenylalanine
  and is this because: if mutant 1 accumulates A then enzyme B-A-lase is mutant 1, R-B-lase is mutant 2, A-D-lase is mutant 3 and 4. and they all have enzymes to synthesis of phenylalanine.
  Just want to make sure i am understanding this. Thanks all
- November 6, 2007 at 5:38 am #77510
  mith
  Participant
  If mutant 1 has inactive form for A->D enzyme, does that mean A accumulates since it cannot be further processed?
- November 6, 2007 at 6:08 am #77511
  jjfptl
  Participant
  Did I confuse something here?
  Now I think I may be lost.
- November 6, 2007 at 2:58 pm #77516
  mith
  Participant
  You said
  if mutant 1 accumulates A then enzyme B-A-lase is mutant
  However, if B->A is mutant, doesn’t that mean that it accumulates B, since it cannot further process it into A?
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