Biology Forum › Community › General Discussion › dominate/recessive gene question
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- December 2, 2008 at 12:27 am #10536defhalotonesParticipant
In a particular breed of cats, Black (B) is Dominant and white (b) is recessive. What are the chances of producing white kittens when crossing a Bb male with a Bb female?
And……
What are the chances of producing black kittens from the above cross?
I cannot figure this one out…
Help please! - December 2, 2008 at 12:43 am #87481Darwin420Participant
OK, this is simple.
Set up a P square.
B b
B BB Bbb Bb bb
So, to have a white cat you have a 25% chance of getting one. 75 % for black cats, 50% for black cats with a recessive trait.
Do you understand what I did here?
- December 2, 2008 at 12:56 am #87482defhalotonesParticipant
thanks for the answer.
And i sorta know what you did there. I’ve been taught how to use the punnet square, but do not know how to ‘accurately’ do it. If you are very bored, could you tell me how you set that up to find the answer using the P-Square? MUCH appreciated
- December 2, 2008 at 1:18 am #87483Darwin420Participant
Ok, I am actually trying to study for an ecology and evolution exam but I can spare a few minutes.
Ok, do you know why we use this square? Look up Mendel’s peas.
Essentially he was some guy who studied pea plants, where he noticed that there must be something passed on to each generation, because he discovered a huge similarity from parent to progeny. He also noticed that there are traits that are recessive and some that are dominant, which we now know as Alleles.
The P square represents the PROBABILITY of getting offspring with particular traits.
For the example you gave me, we are given two traits, correct? B = black fur and is DOMINANT
b= white fur and is recessive
Also keep in mind that when you cross a dominant characteristic with a recessive, only the dominant trait is expressed (assuming no co-dominance is occurring).
So we cross the two heterogeneous ( i.e. Bb) individuals together to see the probability of obtaining white and black cats.
so we write it like this:
Cat one + cat two
Bb Bb = offspringSo all you gotta do is plug it into the P square.
B b
B BB Bbb Bb bb
If you are still having troubles google "punnet square" and see if there are some 101’s on how to do it.
- December 2, 2008 at 7:01 am #87490defhalotonesParticipant
thanks a ton Darwin
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