June 3, 2011 at 3:02 am #15044helpmeplz1Participant
im having a lot of trouble in genetics can someone please explain in detail how to solve this problem.
In humans, brown eye color is dominant to blue eye color. two heterozygous individuals marry and have five children.
a.) What is the probability that all of the children will have blue eyes? i think the answer is 1/32
b.) what is the probability that four of the five will have brown eyes and the other one will have blue eyes? I think the answer is 5(3/4)^4(1/4)^1
c.)What is the probability that the 1st child will have blue , the 2nd will have blue, the 3rd will have brown, the 4th will have blue and the 5th will have brown eyes?
d.)What is the probability that the couple will have 1st a blue eyed boy and 2nd a brown eyed boy?
Im not sure how to solve this I tried with A and B. Please help thank you for your time.
June 3, 2011 at 8:44 am #105149JackBeanParticipant
you obviously know, that the probability, that one child will have blue eyes is 1/4
1) it is (1/4)^5, what should be less than 1/32 I think 😉
2) why do you have there 5?
3) I think that the order should not matter
4) I would guess (1/2*1/4)*(1/2*3/4), rigth?
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