Biology Forum Genetics Homework help!

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    • #10987
      dtbrown
      Participant

      So, I’m taking a Bio course through correspondence and I’m having a hard time wrapping my head around this section.
      Here is my question. Any help would be appreciated and will hopefully get the ball rolling.

      Here is the mRNA strand: AUGACACGCUUACGUUAA

      A) How many nucleotides are there in this strand?
      B) How many codons are there in this strand?
      C) Show the tRNA anticodons that will bond with the mRNA codons.
      D) Show the correct sequence of amino acids coded for by this mRNA.

    • #89431
      sally91
      Participant

      a) its easy just count the letters since each one represent one nucleotide.. and here its 18
      b)i think that each three nucleotides form one codon then there s 6 codons (as i remeber)
      c)im not sure about the tARN but i think it will be : TACTGTGCGAATGCAATT
      d) the correct sequence should be written in a special board on ur book, no one could memorize it, search for it, or ggogle it..
      PS: I TOOK THIS LESSON MANY MONTHS AGO SO IM NOT SURE OF MY ANSWERS SPECIALLY C)
      HOPE IT LL HELP

    • #89432
      dtbrown
      Participant

      That helped a lot thanks! Just figuring out the nucleotides and codons helped me get a good foundation and made it easier to understand and look up the amino acids.

    • #89433
      Harvey23
      Participant

      Hey,

      A)How many nucleotides are there in this strand?
      18
      B) How many codons are there in this strand?
      6
      C) Show the tRNA anticodons that will bond with the mRNA codons.
      UAC UGA GCG AAU GCA AUU
      D) Show the correct sequence of amino acids coded for by this mRNA
      Tyrosine, Cysteine, Alanine, Aspargine, Alanine, Isoleucine

      😉

    • #89480
      MrMistery
      Participant

      wrong on d) harvey..

    • #89773
      Mech
      Participant

      A) Singular strand of nucleotides – therefore we have a total of 18 nucleotides.
      B) A codon consists of three (3) nucleotides – 18/3 = 6.
      C) UAC UGA GCG AAU GCA AUU
      D) I am assuming we are using (AUG ACA CGC UUA CGU UAA):
      1. AUG = Methionine (start codon)
      2. ACA = Threonine
      3. CGC = Arginine
      4. UUA = Leucine
      5. CGU = Arginine
      6. UAA = Stop

      [Not entirely sure about the last, but the sequencing seems to work out correctly]

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