Biology Forum › Community › General Discussion › In the chardakovs experiment…
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- November 1, 2006 at 6:26 pm #6201
osmosischildParticipantRight…
I am confused because in the Chardakovs experiment…
Once the potato chips have been removed from the solution.
And its left with the sucrose solution and the methylene blue stain is the sucrose solution considered to have tissue?
This probably sounds stupid. But I read this passage, and I have now become MORE confused:
The Chardokov method provides a quick means to determine plant tissue water potentials. This method depends on the change in density in a solution that occurs after a tissue has been immersed in it. The solution gains or looses water depending on the water potential of the tissue. If the density of a solution does not change (no net movement of water) then this solution has the same water potential as the tissues that were incubated in it. It is assumed that solute movement between tissue and solution is negligible. Density changes can be observed by watching whether a drop of the original solution floats or sinks in the test solution after tissue incubation. Alternately, for a more accurate measurement of changes in the solution density, a refractometer can be used.
Please help.
Cause I really appreciated the last bit of help I had!
Help makes me content 😀
By the way. I would really appreciate it if you gave me and explination instead/as well as hyperlinks. Because I am not too intelligent, so I can never work things out for myself. 😥
- November 1, 2006 at 8:18 pm #57843mithParticipant
spend some time and think about it. No one said knowledge comes easy.
- November 1, 2006 at 8:24 pm #57844SU_reptileParticipantquote :I am not too intelligent, so I can never work things out for myself.
It’s a pitty for a biologist. Sorry that was a mean joke – I sometimes don’t understand things too so I need somebody else for explanations.
OK, let’s back to the thing. I see it like that:
You have solutions with different concentrations of sucrose and you have also portions of these solutions dyed with methylene blue. You submerge the potato chips, let’s say, in every unstained probe and incubate for about 1,5h and swirl from time to time.
That will cause water flow out from the potato cells or into them by means of osmosis, depending on their water potencial. Then you put the drop of dyed solution (those prepared earlier) in the middle lenght of the sucrose solution depth.
Methylene blue drop will sink, float or stay in place depending on density of the sucrose solution after incubation with potato tissues. The tube with concentration that don’t change position of methylene blue drop has the same water potencial as the cells of that your test potato.
I hope I undersood that approprietly and hope it will help you a bit. Good luck - July 18, 2013 at 12:20 pm #114100sullivanParticipant
The Chardokov system gives a brisk intends to confirm plant tissue water probabilities. This system relies on upon the change in thickness in an answer that happens after a tissue has been drenched in it. The result increases or looses water hinging upon the water potential of the tissue.
- December 16, 2014 at 4:29 am #115592lisaaParticipant
Hello people. I hope we all know quite well about immunology. HIV attacks only T-lymphocytes.
But, we have our innate immunity left and our B-lymphocytes go unaffected by HIV.
The Natural Killer Cells,macrophages,interferons,etc…. we still have many defences left.
Why dont we find a way to stimulate them????????????
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