Biology Forum Molecular Biology Stuck on maths question

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    • #3789
      Sepals
      Participant

      Hi I’m stuck on part of some cw I have to do. I was wondering if any1 could give me any advise please as I can’t seem to work it out on my own.

      This is the info and the questions I’m stuck on are below. Thx. 🙂

      1. In order to be able to use the Gyrase enzyme in the supercoiling assay, the enzyme needs to be diluted. At present it is supplied as 5U/µl in 50% (w/v) glycerol. The glycerol is used to keep the enzyme stable for long term storage but at this concentration it inhibits the Supercoiling Assay. Therefore we need to dilute the enzyme by adding 18µl of Dilution buffer to the tube containing 2µl of DNA gyrase

      Question: After the dilution step how many units of enzyme do you have per µl?
      (Show calculation)

      Question: After the dilution step what is the percentage of glycerol (w/v) in the plasmid DNA solution? (Show calculation)

    • #41865
      sdekivit
      Participant
      quote Sepals:

      Hi I’m stuck on part of some cw I have to do. I was wondering if any1 could give me any advise please as I can’t seem to work it out on my own.

      This is the info and the questions I’m stuck on are below. Thx. 🙂

      1. In order to be able to use the Gyrase enzyme in the supercoiling assay, the enzyme needs to be diluted. At present it is supplied as 5U/µl in 50% (w/v) glycerol. The glycerol is used to keep the enzyme stable for long term storage but at this concentration it inhibits the Supercoiling Assay. Therefore we need to dilute the enzyme by adding 18µl of Dilution buffer to the tube containing 2µl of DNA gyrase

      Question: After the dilution step how many units of enzyme do you have per µl?
      (Show calculation)

      When the first question has been answered, the second one should be easy, so i’ll help you with the first one:

      we have 2 uL of a 5U/uL DNA-gyrase-solution in 50% glycerol stock. Now we add 18 uL of dilution buffer, so the total volume has become 20 uL

      –> this means that the dilution factor is 10 times, so in the diluted solution we have 0,5 U / uL DNA-gyrase.

      (Second method: 5 U/uL –> we have 2 uL, so that means that 2 uL contains 10 units DNA-gyrase.

      The total volume became 20 uL, thus 10 units / 20 uL = 0,5 U/uL DNA-gyrase)

    • #41932
      Sepals
      Participant
      quote sdekivit:

      When the first question has been answered, the second one should be easy, so i’ll help you with the first one:

      we have 2 uL of a 5U/uL DNA-gyrase-solution in 50% glycerol stock. Now we add 18 uL of dilution buffer, so the total volume has become 20 uL

      –> this means that the dilution factor is 10 times, so in the diluted solution we have 0,5 U / uL DNA-gyrase.

      (Second method: 5 U/uL –> we have 2 uL, so that means that 2 uL contains 10 units DNA-gyrase.

      The total volume became 20 uL, thus 10 units / 20 uL = 0,5 U/uL DNA-gyrase)

      Thx a lot for offering to help. I contected a friend who helped me and I used the second method.

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